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core coil with superb results but the 2 diameter was just too big for this application The induction receiver develops a 1 2 mV signal across its internal coil from the fluctuating magnetic field Transistor Q1 provides pre-amplification to drive a headphone amplifier The tone at R3 control varies the amount of gain in the high frequencies Capacitors C1 and C2 block AC hum (C2 also blocks DC to the amplifier input) C3 functions as a low-pass filter to prevent oscillation The output of the volume control at R5 is fed to the input of an LM 386 audio amplifier IC In this configuration the amplifier has a gain of 200 Capacitor C7 and R6 form the output boost circuit which drives the output to the speaker through C6 The output of the LM385 at pin is used to drive an 8 ohm headphone The induction loop receiver circuit can be powered from a 9 volt DC power supplies or batteries Are you ready to begin constructing the induction receiver circuit First you will need to locate a clean, well lit work table or work bench You will want a large table so you can spread out all the components, the diagrams and tools that you will need to build the project Next you will need to locate a small pencil tipped 27 to 33 watt soldering iron and some 60/40 tin/lead rosin core solder for the project Try and locate a small container of Tip Tinner, a soldering iron tip cleaner/dresser which conditions the soldering iron tip; this is available from your local Radio Shack store You should also locate a few small hand tools such as a pair of end-cutters, a pair of needle-nose pliers, a pair of tweezers, a small flat-blade and a Phillips screwdriver and a magnifying glass The induction loop receiver prototype was constructed on a small glass-epoxy circuit board which measured 21/4 3 A circuit board makes for a more reliable and professional circuit Place all the diagrams in front of you on the work table along with all of the components for the induction loop receiver and we will begin building the project The induction loop receiver project contains about four resistors and two potentiometers Locate the resistors using the color chart in Table 15-1, this will help you identify each of the resistors Place the resistors into their respective locations on the circuit board, then solder them in place on the PC board Locate your end-cutters and trim the excess component.

The analysis in 5 assumes that the estimator design model is an exact model of the navigation system error dynamics That assumption is optimistic In the design process, a series of modeling tradeo s may be considered for various reasons including computational loading Due to such tradeo s and the fact that any mathematical model is only an approximation to the actual physical system, the estimator design model will not exactly match the real system Therefore, the analyst should be interested in analyzing the robustness of the system performance to discrepancies between the actual and model systems In addition, the designer may be interested in considering how the system performance would change under di erent sets of design choices, for example, changing the quality of a sensor 6 presents both a method to study the robustness of the system performance to model errors and a method that allows the designer to consider each source of system error separately to determine its contribution to the overall error budget

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Here is a riddle that ought to get your brain running at full speed Consider this infinite product: 1 ( 1) 1 ( 1) 1 ( 1) 1 ( 1) If we start multiplying from left to right, we get a sequence of products that come out like this, in order: 1, 1, 1, 1, 1, 1, 1, 1, The products switch back and forth between 1 and 1, endlessly The final product therefore cannot be defined No integer can have two values at the same time But suppose we try to apply the commutative law to the original expression infinitely many times! We can then rearrange the factors to get this: ( 1) ( 1) 1 1 ( 1) ( 1) 1 1 Now imagine that we try to group the integers in pairs, infinitely many times, like this: [( 1) ( 1)] [1 1] [( 1) ( 1)] [1 1] That gives us 1 1 1 1 The sequence of products in this case is 1, 1, 1, 1, Now it seems as if the product of the whole thing is equal to 1! What s going on

We derived a contradiction here because we improperly used the commutative and grouping laws First, we tried to apply these rules to a product that is undefined in its most basic form Second, we acted as if these rules can be used in a single expression infinitely many times, without really knowing if we can get away with such tricks Evidently we can t!

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